QuestionAugust 15, 2025

Using the reaction above, how much heat (in kJ) will be released from 7.1 moles of NO ? (assuming that NO is the limiting reactant) -812kJ 206 kJ -116kJ -412kJ

Using the reaction above, how much heat (in kJ) will be released from 7.1 moles of NO ? (assuming that NO is the limiting reactant) -812kJ 206 kJ -116kJ -412kJ
Using the reaction above, how
much heat (in kJ) will be
released from 7.1 moles of
NO ? (assuming that NO is the
limiting reactant)
-812kJ
206 kJ
-116kJ
-412kJ

Solution
4.4(264 votes)

Answer

-823.6 \text{ kJ} Explanation 1. Identify the Reaction's Heat Release The reaction releases -116 \text{ kJ} per mole of NO. 2. Calculate Total Heat Released Multiply the heat release per mole by the number of moles: 7.1 \times (-116) = -823.6 \text{ kJ}.

Explanation

1. Identify the Reaction's Heat Release<br /> The reaction releases $-116 \text{ kJ}$ per mole of $NO$.<br /><br />2. Calculate Total Heat Released<br /> Multiply the heat release per mole by the number of moles: $7.1 \times (-116) = -823.6 \text{ kJ}$.
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