QuestionJuly 17, 2025

Which equation has an a-value of -2 a b-value of 1, and ac-value of 3? 0=-2x^2+x+3 0=2x^2+x+3 0=-2x^2+3 0=2x^2-x+3

Which equation has an a-value of -2 a b-value of 1, and ac-value of 3? 0=-2x^2+x+3 0=2x^2+x+3 0=-2x^2+3 0=2x^2-x+3
Which equation has an a-value of -2 a b-value of 1, and ac-value of 3? 0=-2x^2+x+3 0=2x^2+x+3 0=-2x^2+3 0=2x^2-x+3

Solution
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Answer

0 = -2x^{2} + x + 3 Explanation 1. Identify the coefficients The equation is in the form ax^2 + bx + c = 0. We need a = -2, b = 1, and c = 3. 2. Match coefficients to equations Compare each given equation with the required coefficients: - 0 = -2x^{2} + x + 3: Matches a = -2, b = 1, c = 3. - 0 = 2x^{2} + x + 3: a = 2, does not match. - 0 = -2x^{2} + 3: Missing b term, does not match. - 0 = 2x^{2} - x + 3: a = 2, does not match.

Explanation

1. Identify the coefficients<br /> The equation is in the form $ax^2 + bx + c = 0$. We need $a = -2$, $b = 1$, and $c = 3$.<br /><br />2. Match coefficients to equations<br /> Compare each given equation with the required coefficients:<br />- $0 = -2x^{2} + x + 3$: Matches $a = -2$, $b = 1$, $c = 3$.<br />- $0 = 2x^{2} + x + 3$: $a = 2$, does not match.<br />- $0 = -2x^{2} + 3$: Missing $b$ term, does not match.<br />- $0 = 2x^{2} - x + 3$: $a = 2$, does not match.
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