QuestionAugust 26, 2025

What is an equation of the line that passes through the points (-3,1) and (-4,0) Answer Attempt 1 out of 2 square

What is an equation of the line that passes through the points (-3,1) and (-4,0) Answer Attempt 1 out of 2 square
What is an equation of the line that
passes through the points (-3,1) and
(-4,0)
Answer
Attempt 1 out of 2
square

Solution
4.1(251 votes)

Answer

y = x + 4 Explanation 1. Calculate the slope Use the formula for slope: **m = \frac{y_2 - y_1}{x_2 - x_1}**. Here, (x_1, y_1) = (-3, 1) and (x_2, y_2) = (-4, 0). So, m = \frac{0 - 1}{-4 + 3} = \frac{-1}{-1} = 1. 2. Use point-slope form The point-slope form is **y - y_1 = m(x - x_1)**. Using point (-3, 1) and slope m = 1, we have y - 1 = 1(x + 3). 3. Simplify to slope-intercept form Simplify y - 1 = x + 3 to get y = x + 4.

Explanation

1. Calculate the slope<br /> Use the formula for slope: **$m = \frac{y_2 - y_1}{x_2 - x_1}$**. Here, $(x_1, y_1) = (-3, 1)$ and $(x_2, y_2) = (-4, 0)$. So, $m = \frac{0 - 1}{-4 + 3} = \frac{-1}{-1} = 1$.<br />2. Use point-slope form<br /> The point-slope form is **$y - y_1 = m(x - x_1)$**. Using point $(-3, 1)$ and slope $m = 1$, we have $y - 1 = 1(x + 3)$.<br />3. Simplify to slope-intercept form<br /> Simplify $y - 1 = x + 3$ to get $y = x + 4$.
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