QuestionJuly 8, 2025

An electron component has a voltage drop of 25 volts and an impedance of 10 ohms.How much power is being dissipated by this component? 92.5 W 72.5 W 82.5 W 62.5 W

An electron component has a voltage drop of 25 volts and an impedance of 10 ohms.How much power is being dissipated by this component? 92.5 W 72.5 W 82.5 W 62.5 W
An electron component has a voltage drop of 25 volts and an impedance of 10 ohms.How much
power is being dissipated by this component?
92.5 W
72.5 W
82.5 W
62.5 W

Solution
4.0(266 votes)

Answer

62.5 W Explanation 1. Identify the formula for power dissipation Use the formula for power dissipation in electrical components: **P = \frac{V^2}{R}**, where P is power, V is voltage, and R is resistance (impedance). 2. Substitute values into the formula Substitute V = 25 volts and R = 10 ohms into the formula: P = \frac{25^2}{10}. 3. Calculate the power Calculate: P = \frac{625}{10} = 62.5 watts.

Explanation

1. Identify the formula for power dissipation<br /> Use the formula for power dissipation in electrical components: **$P = \frac{V^2}{R}$**, where $P$ is power, $V$ is voltage, and $R$ is resistance (impedance).<br />2. Substitute values into the formula<br /> Substitute $V = 25$ volts and $R = 10$ ohms into the formula: $P = \frac{25^2}{10}$.<br />3. Calculate the power<br /> Calculate: $P = \frac{625}{10} = 62.5$ watts.
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