QuestionAugust 26, 2025

The endpoint of the line CD are C(-3,-2) to D(6,1) What are the coordinates of the point Z such that it partitions line CD into a ratio of 2 to 1. square square

The endpoint of the line CD are C(-3,-2) to D(6,1) What are the coordinates of the point Z such that it partitions line CD into a ratio of 2 to 1. square square
The endpoint of the line CD are C(-3,-2) to D(6,1) What are the coordinates
of the point Z such that it partitions line CD into a ratio of 2 to 1.
square  square

Solution
4.7(246 votes)

Answer

(3, 0) Explanation 1. Identify the formula for sectioning a line Use the section formula for internal division: **Z(x, y) = \left(\frac{mx_2 + nx_1}{m+n}, \frac{my_2 + ny_1}{m+n}\right)** where m:n is the ratio. 2. Apply the formula to find x-coordinate of Z For x: Z_x = \frac{2 \cdot 6 + 1 \cdot (-3)}{2+1} = \frac{12 - 3}{3} = \frac{9}{3} = 3. 3. Apply the formula to find y-coordinate of Z For y: Z_y = \frac{2 \cdot 1 + 1 \cdot (-2)}{2+1} = \frac{2 - 2}{3} = \frac{0}{3} = 0.

Explanation

1. Identify the formula for sectioning a line<br /> Use the section formula for internal division: **$Z(x, y) = \left(\frac{mx_2 + nx_1}{m+n}, \frac{my_2 + ny_1}{m+n}\right)$** where $m:n$ is the ratio.<br />2. Apply the formula to find x-coordinate of Z<br /> For $x$: $Z_x = \frac{2 \cdot 6 + 1 \cdot (-3)}{2+1} = \frac{12 - 3}{3} = \frac{9}{3} = 3$.<br />3. Apply the formula to find y-coordinate of Z<br /> For $y$: $Z_y = \frac{2 \cdot 1 + 1 \cdot (-2)}{2+1} = \frac{2 - 2}{3} = \frac{0}{3} = 0$.
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