QuestionMay 5, 2025

For a given motor vehicle, the maximum achievable deceleration from braking is approximately 7m/sec^2 on dry concrete. On wet asphalt, it is approximately 2.8m/sec^2 Given that 1 mph corresponds to 0.447m/sec find the total distance that a car travels in meters on dry concrete after the brakes are applied until it comes to a complete stop if the initial velocity is 67 mph (30m/sec) or if the initial braking velocity is 56 mph (25m/sec) (Round your answers to one decimal place.) 67 mph (30m/sec) square lm 56 mph (25m/sec) square m Find the corresponding distances if the surface is slippery wet asphalt. 67 mph (30m/sec) square lm 56 mph (25m/sec) square lm

For a given motor vehicle, the maximum achievable deceleration from braking is approximately 7m/sec^2 on dry concrete. On wet asphalt, it is approximately 2.8m/sec^2 Given that 1 mph corresponds to 0.447m/sec find the total distance that a car travels in meters on dry concrete after the brakes are applied until it comes to a complete stop if the initial velocity is 67 mph (30m/sec) or if the initial braking velocity is 56 mph (25m/sec) (Round your answers to one decimal place.) 67 mph (30m/sec) square lm 56 mph (25m/sec) square m Find the corresponding distances if the surface is slippery wet asphalt. 67 mph (30m/sec) square lm 56 mph (25m/sec) square lm
For a given motor vehicle, the maximum achievable deceleration from braking is approximately 7m/sec^2 on dry concrete. On wet asphalt, it is approximately 2.8m/sec^2 Given that 1 mph corresponds to 0.447m/sec find the total distance that a car travels in meters on dry concrete after the brakes are applied until it comes to a complete stop if the initial velocity is 67 mph (30m/sec) or if the initial braking velocity is 56 mph (25m/sec) (Round your answers to one decimal place.) 67 mph (30m/sec) square lm 56 mph (25m/sec) square m Find the corresponding distances if the surface is slippery wet asphalt. 67 mph (30m/sec) square lm 56 mph (25m/sec) square lm

Solution
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Answer

Dry concrete (67 mph): 64.3 m ### Dry concrete (56 mph): 44.6 m ### Wet asphalt (67 mph): 160.7 m ### Wet asphalt (56 mph): 111.6 m Explanation 1. Calculate stopping distance on dry concrete Use the formula d = \frac{v^2}{2a} where v is initial velocity and a is deceleration. For 67 mph (30 \, m/sec), d = \frac{30^2}{2 \times 7}. For 56 mph (25 \, m/sec), d = \frac{25^2}{2 \times 7}. 2. Calculate stopping distance on wet asphalt Use the same formula d = \frac{v^2}{2a} with a = 2.8 \, m/sec^2. For 67 mph (30 \, m/sec), d = \frac{30^2}{2 \times 2.8}. For 56 mph (25 \, m/sec), d = \frac{25^2}{2 \times 2.8}.

Explanation

1. Calculate stopping distance on dry concrete<br /> Use the formula $d = \frac{v^2}{2a}$ where $v$ is initial velocity and $a$ is deceleration. For 67 mph ($30 \, m/sec$), $d = \frac{30^2}{2 \times 7}$. For 56 mph ($25 \, m/sec$), $d = \frac{25^2}{2 \times 7}$.<br /><br />2. Calculate stopping distance on wet asphalt<br /> Use the same formula $d = \frac{v^2}{2a}$ with $a = 2.8 \, m/sec^2$. For 67 mph ($30 \, m/sec$), $d = \frac{30^2}{2 \times 2.8}$. For 56 mph ($25 \, m/sec$), $d = \frac{25^2}{2 \times 2.8}$.
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