QuestionAugust 26, 2025

Let A and B be mutually exclusive events with P(A)=(1)/(4) and P(B)=(1)/(5) What is P(AorB) Write your answer as a fraction or decimal.Do not round. square

Let A and B be mutually exclusive events with P(A)=(1)/(4) and P(B)=(1)/(5) What is P(AorB) Write your answer as a fraction or decimal.Do not round. square
Let A and B be mutually exclusive events with P(A)=(1)/(4) and P(B)=(1)/(5)
What is P(AorB)
Write your answer as a fraction or decimal.Do not round.
square

Solution
3.6(245 votes)

Answer

\frac{9}{20} Explanation 1. Identify the formula for mutually exclusive events For mutually exclusive events, **P(A \cup B) = P(A) + P(B)**. 2. Substitute given probabilities P(A) = \frac{1}{4} and P(B) = \frac{1}{5}. Therefore, P(A \cup B) = \frac{1}{4} + \frac{1}{5}. 3. Calculate the sum Convert to a common denominator: \frac{1}{4} = \frac{5}{20} and \frac{1}{5} = \frac{4}{20}. Thus, P(A \cup B) = \frac{5}{20} + \frac{4}{20} = \frac{9}{20}.

Explanation

1. Identify the formula for mutually exclusive events<br /> For mutually exclusive events, **$P(A \cup B) = P(A) + P(B)$**.<br /><br />2. Substitute given probabilities<br /> $P(A) = \frac{1}{4}$ and $P(B) = \frac{1}{5}$. Therefore, $P(A \cup B) = \frac{1}{4} + \frac{1}{5}$.<br /><br />3. Calculate the sum<br /> Convert to a common denominator: $\frac{1}{4} = \frac{5}{20}$ and $\frac{1}{5} = \frac{4}{20}$. Thus, $P(A \cup B) = \frac{5}{20} + \frac{4}{20} = \frac{9}{20}$.
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