QuestionAugust 26, 2025

Determine the number of solutions to the quadratic equation x^2+4x-12=0 The equation has square real solution(s) because the discriminant is n/ square , which is zero.

Determine the number of solutions to the quadratic equation x^2+4x-12=0 The equation has square real solution(s) because the discriminant is n/ square , which is zero.
Determine the number of solutions to the quadratic equation x^2+4x-12=0
The equation has square  real solution(s) because the discriminant is n/ square  , which is
zero.

Solution
4.1(255 votes)

Answer

The equation has 2 real solutions. Explanation 1. Calculate the Discriminant Use the formula for the discriminant: D = b^2 - 4ac. Here, a = 1, b = 4, and c = -12. D = 4^2 - 4 \cdot 1 \cdot (-12) = 16 + 48 = 64. 2. Determine the Number of Solutions Since the discriminant D = 64 > 0, there are two distinct real solutions.

Explanation

1. Calculate the Discriminant<br /> Use the formula for the discriminant: $D = b^2 - 4ac$. Here, $a = 1$, $b = 4$, and $c = -12$.<br /> $D = 4^2 - 4 \cdot 1 \cdot (-12) = 16 + 48 = 64$.<br /><br />2. Determine the Number of Solutions<br /> Since the discriminant $D = 64 > 0$, there are two distinct real solutions.
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