QuestionDecember 12, 2025

Use the quadratic formula to solve -2x^2+9x-11=0 x=-5(3)/(4) and -12(1)/(4) x=(9)/(4)pm (sqrt (7))/(4) x=-1 and (11)/(2) no real solutions

Use the quadratic formula to solve -2x^2+9x-11=0 x=-5(3)/(4) and -12(1)/(4) x=(9)/(4)pm (sqrt (7))/(4) x=-1 and (11)/(2) no real solutions
Use the quadratic formula to solve -2x^2+9x-11=0
x=-5(3)/(4) and -12(1)/(4)
x=(9)/(4)pm (sqrt (7))/(4)
x=-1 and (11)/(2)
no real solutions

Solution
4.4(318 votes)

Answer

no real solutions Explanation 1. Identify coefficients a = -2, b = 9, c = -11 2. Apply quadratic formula Use \displaystyle x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} 3. Calculate discriminant b^2 - 4ac = 9^2 - 4(-2)(-11) = 81 - 88 = -7 4. Analyze discriminant Discriminant is negative, so no real solutions.

Explanation

1. Identify coefficients<br /> $a = -2$, $b = 9$, $c = -11$<br />2. Apply quadratic formula<br /> Use $\displaystyle x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$<br />3. Calculate discriminant<br /> $b^2 - 4ac = 9^2 - 4(-2)(-11) = 81 - 88 = -7$<br />4. Analyze discriminant<br /> Discriminant is negative, so no real solutions.
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