QuestionApril 30, 2025

A candle is 11.0 cm from a converging lens, and an inverted . real image is created 88 .0 cm away from the lens.What is the magnification of the image? -0.125 -8.00 +0.125 +8.00

A candle is 11.0 cm from a converging lens, and an inverted . real image is created 88 .0 cm away from the lens.What is the magnification of the image? -0.125 -8.00 +0.125 +8.00
A candle is 11.0 cm from a
converging lens, and an inverted . real
image is created 88 .0 cm away from
the lens.What is the magnification of
the image?
-0.125
-8.00
+0.125
+8.00

Solution
3.9(327 votes)

Answer

-8.00 Explanation 1. Identify the given values Object distance d_o = 11.0 \, \text{cm}, Image distance d_i = 88.0 \, \text{cm}. 2. Use magnification formula **Magnification** m = -\frac{d_i}{d_o}. 3. Calculate magnification Substitute the values: m = -\frac{88.0}{11.0} = -8.00.

Explanation

1. Identify the given values<br /> Object distance $d_o = 11.0 \, \text{cm}$, Image distance $d_i = 88.0 \, \text{cm}$.<br /><br />2. Use magnification formula<br /> **Magnification** $m = -\frac{d_i}{d_o}$.<br /><br />3. Calculate magnification<br /> Substitute the values: $m = -\frac{88.0}{11.0} = -8.00$.
Click to rate:

Similar Questions