QuestionMay 23, 2025

Translate the following instruction into 32 bits: add 8, 3, 5 A) 1000000100000101 00100 00000100000 B) 00000000100000110100000000100000 C) 00000000011001000100000000100000 D) 00000000011001010100000000100000 E) 10000001000001010010000000000000

Translate the following instruction into 32 bits: add 8, 3, 5 A) 1000000100000101 00100 00000100000 B) 00000000100000110100000000100000 C) 00000000011001000100000000100000 D) 00000000011001010100000000100000 E) 10000001000001010010000000000000
Translate the following instruction into 32 bits: add 8, 3, 5 A) 1000000100000101 00100 00000100000 B) 00000000100000110100000000100000 C) 00000000011001000100000000100000 D) 00000000011001010100000000100000 E) 10000001000001010010000000000000

Solution
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Answer

B) 00000000100000110100000000100000 Explanation 1. Identify the instruction format The `add` instruction is an R-type instruction in MIPS. 2. Determine opcode and function code Opcode for R-type is 000000, and function code for `add` is 100000. 3. Determine register numbers \8 is t0, \3 is v1, \5 is a1. Their binary representations are 01000, 00011, and 00101 respectively. 4. Construct the 32-bit instruction Format: opcode (6 bits) | rs (5 bits) | rt (5 bits) | rd (5 bits) | shamt (5 bits) | funct (6 bits). Result: 000000 00011 00101 01000 00000 100000

Explanation

1. Identify the instruction format<br /> The `add` instruction is an R-type instruction in MIPS.<br />2. Determine opcode and function code<br /> Opcode for R-type is 000000, and function code for `add` is 100000.<br />3. Determine register numbers<br /> $\$8$ is $t0$, $\$3$ is $v1$, $\$5$ is $a1$. Their binary representations are 01000, 00011, and 00101 respectively.<br />4. Construct the 32-bit instruction<br /> Format: opcode (6 bits) | rs (5 bits) | rt (5 bits) | rd (5 bits) | shamt (5 bits) | funct (6 bits).<br /> Result: 000000 00011 00101 01000 00000 100000
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