QuestionJune 4, 2025

A student uses 0.507 kilograms of lead (II)fluorosilicate, PbSiF_(6) to make a 3.75L solution of aqueous lead (I) fluorosilicate . Determine the concentration . of the solution . Round your answer to three significant figures. Include the unit in your answer. Answer: square

A student uses 0.507 kilograms of lead (II)fluorosilicate, PbSiF_(6) to make a 3.75L solution of aqueous lead (I) fluorosilicate . Determine the concentration . of the solution . Round your answer to three significant figures. Include the unit in your answer. Answer: square
A student uses 0.507 kilograms of lead
(II)fluorosilicate, PbSiF_(6) to make a 3.75L
solution of aqueous lead (I)
fluorosilicate . Determine the
concentration . of the solution . Round
your answer to three significant figures.
Include the unit in your answer.
Answer:
square

Solution
4.0(244 votes)

Answer

0.387 mol/L Explanation 1. Calculate Molar Mass of PbSiF_6 Molar mass = 207.2 \, (Pb) + 28.09 \, (Si) + 6 \times 18.998 \, (F) = 349.3 \, \text{g/mol} 2. Convert Mass to Moles Moles of PbSiF_6 = \frac{0.507 \, \text{kg} \times 1000 \, \text{g/kg}}{349.3 \, \text{g/mol}} = 1.451 \, \text{mol} 3. Calculate Concentration **Concentration** C = \frac{\text{moles}}{\text{volume in L}} = \frac{1.451 \, \text{mol}}{3.75 \, \text{L}} = 0.387 \, \text{mol/L}

Explanation

1. Calculate Molar Mass of $PbSiF_6$<br /> Molar mass = $207.2 \, (Pb) + 28.09 \, (Si) + 6 \times 18.998 \, (F) = 349.3 \, \text{g/mol}$<br /><br />2. Convert Mass to Moles<br /> Moles of $PbSiF_6 = \frac{0.507 \, \text{kg} \times 1000 \, \text{g/kg}}{349.3 \, \text{g/mol}} = 1.451 \, \text{mol}$<br /><br />3. Calculate Concentration<br /> **Concentration** $C = \frac{\text{moles}}{\text{volume in L}} = \frac{1.451 \, \text{mol}}{3.75 \, \text{L}} = 0.387 \, \text{mol/L}$
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