QuestionMay 6, 2025

5.50 g of KOH in 2.50 L of a KOH solution Express your answer with the appropriate units.

5.50 g of KOH in 2.50 L of a KOH solution Express your answer with the appropriate units.
5.50 g of KOH in 2.50 L of a KOH solution Express your answer with the appropriate units.

Solution
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Answer

0.0392 \, \text{M} Explanation 1. Calculate the moles of KOH Molar mass of KOH = 39.10 + 16.00 + 1.01 = 56.11 \, \text{g/mol}. Moles of KOH = \frac{\text{mass}}{\text{molar mass}} = \frac{5.50}{56.11} = 0.098 \, \text{mol}. 2. Calculate molarity Molarity = \frac{\text{moles of solute}}{\text{volume of solution in liters}} = \frac{0.098}{2.50} = 0.0392 \, \text{M}.

Explanation

1. Calculate the moles of KOH<br /> Molar mass of KOH = $39.10 + 16.00 + 1.01 = 56.11 \, \text{g/mol}$. <br />Moles of KOH = $\frac{\text{mass}}{\text{molar mass}} = \frac{5.50}{56.11} = 0.098 \, \text{mol}$.<br /><br />2. Calculate molarity<br /> Molarity = $\frac{\text{moles of solute}}{\text{volume of solution in liters}} = \frac{0.098}{2.50} = 0.0392 \, \text{M}$.
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