QuestionJune 21, 2025

Calculate the grams of SO_(2) gas present at STP in a 5.9 L container. 0.249 0.269 15g 17g 649

Calculate the grams of SO_(2) gas present at STP in a 5.9 L container. 0.249 0.269 15g 17g 649
Calculate the grams of SO_(2)
gas present at STP in a 5.9 L container.
0.249
0.269
15g
17g
649

Solution
4.3(353 votes)

Answer

17 g Explanation 1. Use Ideal Gas Law at STP At STP, 1 mole of gas occupies 22.4 L. Calculate moles of SO_2 using the formula: **moles = \frac{\text{volume}}{\text{molar volume at STP}}**. 2. Calculate Moles of SO_2 Moles of SO_2 = \frac{5.9 \, \text{L}}{22.4 \, \text{L/mol}} = 0.26339 \, \text{mol}. 3. Calculate Mass of SO_2 Molar mass of SO_2 = 64 \, \text{g/mol}. Mass = moles \times molar mass = 0.26339 \, \text{mol} \times 64 \, \text{g/mol} = 16.88 \, \text{g}.

Explanation

1. Use Ideal Gas Law at STP<br /> At STP, 1 mole of gas occupies 22.4 L. Calculate moles of $SO_2$ using the formula: **moles = \frac{\text{volume}}{\text{molar volume at STP}}**.<br /><br />2. Calculate Moles of $SO_2$<br /> Moles of $SO_2 = \frac{5.9 \, \text{L}}{22.4 \, \text{L/mol}} = 0.26339 \, \text{mol}$.<br /><br />3. Calculate Mass of $SO_2$<br /> Molar mass of $SO_2 = 64 \, \text{g/mol}$. Mass = moles $\times$ molar mass = $0.26339 \, \text{mol} \times 64 \, \text{g/mol} = 16.88 \, \text{g}$.
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