QuestionJune 22, 2025

A 10.5 g sample of titanium at 63.0^circ C is warmeo I to 85.0^circ C How much energy is needed to warm the metal? (c_(Ti)=0.544(J)/(gcdot ^circ )C) q=[?]J

A 10.5 g sample of titanium at 63.0^circ C is warmeo I to 85.0^circ C How much energy is needed to warm the metal? (c_(Ti)=0.544(J)/(gcdot ^circ )C) q=[?]J
A 10.5 g sample of titanium at
63.0^circ C is warmeo I to 85.0^circ C
How much energy is needed to
warm the metal?
(c_(Ti)=0.544(J)/(gcdot ^circ )C)
q=[?]J

Solution
4.1(126 votes)

Answer

125.136 J Explanation 1. Identify the formula Use the formula for heat energy: **q = mc\Delta T**. 2. Calculate \Delta T \Delta T = 85.0^{\circ}C - 63.0^{\circ}C = 22.0^{\circ}C. 3. Substitute values into the formula q = (10.5 \, \text{g})(0.544 \, \frac{\text{J}}{\text{g}\cdot^{\circ}\text{C}})(22.0^{\circ}C). 4. Perform the calculation q = 125.136 \, \text{J}.

Explanation

1. Identify the formula<br /> Use the formula for heat energy: **$q = mc\Delta T$**.<br /><br />2. Calculate $\Delta T$<br /> $\Delta T = 85.0^{\circ}C - 63.0^{\circ}C = 22.0^{\circ}C$.<br /><br />3. Substitute values into the formula<br /> $q = (10.5 \, \text{g})(0.544 \, \frac{\text{J}}{\text{g}\cdot^{\circ}\text{C}})(22.0^{\circ}C)$.<br /><br />4. Perform the calculation<br /> $q = 125.136 \, \text{J}$.
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