QuestionJune 24, 2025

How many moles of NaOH are needed to neutralize 15.0 mL of 0.235 M HCl solution? Hints: Don't forget to write the equation, balance it, and make sure units of volume are consistant 0.00353 moles 35.3 moles 0.235 moles 3.53 moles 23.5 moles 2.35 moles

How many moles of NaOH are needed to neutralize 15.0 mL of 0.235 M HCl solution? Hints: Don't forget to write the equation, balance it, and make sure units of volume are consistant 0.00353 moles 35.3 moles 0.235 moles 3.53 moles 23.5 moles 2.35 moles
How many moles of NaOH are needed to neutralize 15.0 mL of 0.235 M HCl solution?
Hints: Don't forget to write the equation, balance it, and make sure units of volume are consistant
0.00353 moles
35.3 moles
0.235 moles
3.53 moles
23.5 moles
2.35 moles

Solution
4.6(211 votes)

Answer

0.00353 moles Explanation 1. Write and Balance the Equation The neutralization reaction is \text{NaOH} + \text{HCl} \rightarrow \text{NaCl} + \text{H}_2\text{O} . It is already balanced. 2. Calculate Moles of HCl Use the formula ** n = C \times V **, where n is moles, C is concentration (0.235 M), and V is volume in liters (15.0 mL = 0.015 L). So, n = 0.235 \times 0.015 = 0.003525 moles of HCl. 3. Determine Moles of NaOH Needed From the balanced equation, 1 mole of NaOH reacts with 1 mole of HCl. Therefore, 0.003525 moles of NaOH are needed.

Explanation

1. Write and Balance the Equation<br /> The neutralization reaction is $ \text{NaOH} + \text{HCl} \rightarrow \text{NaCl} + \text{H}_2\text{O} $. It is already balanced.<br /><br />2. Calculate Moles of HCl<br /> Use the formula **$ n = C \times V $**, where $ n $ is moles, $ C $ is concentration (0.235 M), and $ V $ is volume in liters (15.0 mL = 0.015 L). So, $ n = 0.235 \times 0.015 = 0.003525 $ moles of HCl.<br /><br />3. Determine Moles of NaOH Needed<br /> From the balanced equation, 1 mole of NaOH reacts with 1 mole of HCl. Therefore, 0.003525 moles of NaOH are needed.
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