QuestionAugust 26, 2025

What is the weighted average of the numbers 2 and 14 with weight 1/4 on the first number and 3/4 on the second number? square

What is the weighted average of the numbers 2 and 14 with weight 1/4 on the first number and 3/4 on the second number? square
What is the weighted average of the numbers 2 and
14 with weight 1/4 on the first number and 3/4 on the
second number?
square

Solution
4.4(232 votes)

Answer

11 Explanation 1. Apply the Weighted Average Formula Use the formula for weighted average: ** \text{Weighted Average} = \frac{w_1 \cdot x_1 + w_2 \cdot x_2}{w_1 + w_2} ** where w_1 = \frac{1}{4}, x_1 = 2, w_2 = \frac{3}{4}, and x_2 = 14. 2. Calculate the Numerator Compute w_1 \cdot x_1 + w_2 \cdot x_2 = \frac{1}{4} \cdot 2 + \frac{3}{4} \cdot 14 = \frac{2}{4} + \frac{42}{4} = \frac{44}{4}. 3. Simplify the Expression Since w_1 + w_2 = 1, the weighted average simplifies to \frac{44}{4} = 11.

Explanation

1. Apply the Weighted Average Formula<br /> Use the formula for weighted average: **$ \text{Weighted Average} = \frac{w_1 \cdot x_1 + w_2 \cdot x_2}{w_1 + w_2} $** where $w_1 = \frac{1}{4}$, $x_1 = 2$, $w_2 = \frac{3}{4}$, and $x_2 = 14$.<br />2. Calculate the Numerator<br /> Compute $w_1 \cdot x_1 + w_2 \cdot x_2 = \frac{1}{4} \cdot 2 + \frac{3}{4} \cdot 14 = \frac{2}{4} + \frac{42}{4} = \frac{44}{4}$.<br />3. Simplify the Expression<br /> Since $w_1 + w_2 = 1$, the weighted average simplifies to $\frac{44}{4} = 11$.
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