QuestionMay 13, 2025

The force between a pair of .005 charges is 750 N. What is the distance between them? 3.75 m 17 m 300 m 23 m

The force between a pair of .005 charges is 750 N. What is the distance between them? 3.75 m 17 m 300 m 23 m
The force between a pair of .005 charges is 750 N. What is the distance between them? 3.75 m 17 m 300 m 23 m

Solution
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Answer

3.75 m Explanation 1. Use Coulomb's Law The formula for the force between two charges is F = k \frac{|q_1 q_2|}{r^2}, where k = 8.99 \times 10^9 \, \text{N m}^2/\text{C}^2, q_1 = q_2 = 0.005 \, \text{C}, and F = 750 \, \text{N}. 2. Solve for Distance Rearrange the formula to find r: r = \sqrt{\frac{k |q_1 q_2|}{F}}. Substitute the values: r = \sqrt{\frac{8.99 \times 10^9 \times (0.005)^2}{750}}.

Explanation

1. Use Coulomb's Law<br /> The formula for the force between two charges is $F = k \frac{|q_1 q_2|}{r^2}$, where $k = 8.99 \times 10^9 \, \text{N m}^2/\text{C}^2$, $q_1 = q_2 = 0.005 \, \text{C}$, and $F = 750 \, \text{N}$.<br />2. Solve for Distance<br /> Rearrange the formula to find $r$: $r = \sqrt{\frac{k |q_1 q_2|}{F}}$. Substitute the values: $r = \sqrt{\frac{8.99 \times 10^9 \times (0.005)^2}{750}}$.
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