QuestionMay 7, 2025

What mass of steam is required to release 497,000 kJ of heat?

What mass of steam is required to release 497,000 kJ of heat?
What mass of steam is required to release 497,000 kJ of heat?

Solution
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Answer

219.91 \text{ kg} Explanation 1. Identify the formula for heat release Use the formula Q = m \cdot L_v, where Q is the heat released, m is the mass of steam, and L_v is the latent heat of vaporization. 2. Rearrange the formula to solve for mass Rearrange to m = \frac{Q}{L_v}. 3. Substitute known values Given Q = 497,000 \text{ kJ} and L_v = 2260 \text{ kJ/kg} (latent heat of vaporization for water), substitute into the equation: m = \frac{497,000}{2260}.

Explanation

1. Identify the formula for heat release<br /> Use the formula $Q = m \cdot L_v$, where $Q$ is the heat released, $m$ is the mass of steam, and $L_v$ is the latent heat of vaporization.<br />2. Rearrange the formula to solve for mass<br /> Rearrange to $m = \frac{Q}{L_v}$.<br />3. Substitute known values<br /> Given $Q = 497,000 \text{ kJ}$ and $L_v = 2260 \text{ kJ/kg}$ (latent heat of vaporization for water), substitute into the equation: $m = \frac{497,000}{2260}$.
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