Amaya is standing 30 ft from a volleybal I net. The net is 8 ft high. Amaya serves the ball. The path of the ball is modeled by the equation y=-0.02(x-18)^2+12 , where x is the ball's horizontal distance in feet from Amaya's position and y is the distance in feet from the ground to the ball. a. How far away is the ball from Amaya when it is at its maximum height?Explain. b. Describe how you would find the ball's height when it crosses the net at x=30 a. How far away is the ball from Amaya when it is at its maximum height?Explain. The ball is square ft away from Amaya when it is at its maximum height. Use the square of the vertex.

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