QuestionJune 28, 2025

Find the conductivity of a conduit with a cross-sectional area of 0.750cm^2 and a length of 15.0 cm, given that its conductance G is 0.500ohm^-1. 18ohm^-1cm^-1 10.0ohm^-1 2.0ohm^-1cm^-1 5.0ohm^-1cm^-1

Find the conductivity of a conduit with a cross-sectional area of 0.750cm^2 and a length of 15.0 cm, given that its conductance G is 0.500ohm^-1. 18ohm^-1cm^-1 10.0ohm^-1 2.0ohm^-1cm^-1 5.0ohm^-1cm^-1
Find the conductivity of a conduit with a cross-sectional area of 0.750cm^2 and a length of 15.0 cm, given that its
conductance G is 0.500ohm^-1.
18ohm^-1cm^-1
10.0ohm^-1
2.0ohm^-1cm^-1
5.0ohm^-1cm^-1

Solution
4.5(304 votes)

Answer

10.0 \, \text{ohm}^{-1}\text{cm}^{-1} Explanation 1. Identify the relationship between conductance and conductivity Conductivity \sigma is related to conductance G by the formula: **\sigma = G \cdot \frac{L}{A}**, where L is the length and A is the cross-sectional area. 2. Substitute given values into the formula Given G = 0.500 \, \text{ohm}^{-1}, L = 15.0 \, \text{cm}, and A = 0.750 \, \text{cm}^2, substitute these into the formula: \sigma = 0.500 \cdot \frac{15.0}{0.750}. 3. Calculate the conductivity \sigma = 0.500 \cdot 20 = 10.0 \, \text{ohm}^{-1}\text{cm}^{-1}.

Explanation

1. Identify the relationship between conductance and conductivity<br /> Conductivity $\sigma$ is related to conductance $G$ by the formula: **$\sigma = G \cdot \frac{L}{A}$**, where $L$ is the length and $A$ is the cross-sectional area.<br /><br />2. Substitute given values into the formula<br /> Given $G = 0.500 \, \text{ohm}^{-1}$, $L = 15.0 \, \text{cm}$, and $A = 0.750 \, \text{cm}^2$, substitute these into the formula: $\sigma = 0.500 \cdot \frac{15.0}{0.750}$.<br /><br />3. Calculate the conductivity<br /> $\sigma = 0.500 \cdot 20 = 10.0 \, \text{ohm}^{-1}\text{cm}^{-1}$.
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