QuestionAugust 15, 2025

A 5 kg bowling ball is dropped and hits the ground at 18.8m/s What height was the ball dropped from?(answer in m) Your Answer: square square Answer units

A 5 kg bowling ball is dropped and hits the ground at 18.8m/s What height was the ball dropped from?(answer in m) Your Answer: square square Answer units
A 5 kg bowling ball is dropped and hits the ground at 18.8m/s What height was the ball dropped from?(answer in m) Your Answer: square square Answer units

Solution
4.7(161 votes)

Answer

18.01 m Explanation 1. Identify the formula Use the formula for gravitational potential energy and kinetic energy: **mgh = \frac{1}{2}mv^2**. 2. Cancel mass from both sides Since mass m appears on both sides, it cancels out: **gh = \frac{1}{2}v^2**. 3. Solve for height h Rearrange to find h: **h = \frac{v^2}{2g}**. 4. Substitute known values Substitute v = 18.8 \, \text{m/s} and g = 9.81 \, \text{m/s}^2: h = \frac{(18.8)^2}{2 \times 9.81}. 5. Calculate the height Compute the value: h = \frac{353.44}{19.62} \approx 18.01 \, \text{m}.

Explanation

1. Identify the formula<br /> Use the formula for gravitational potential energy and kinetic energy: **$mgh = \frac{1}{2}mv^2$**.<br /><br />2. Cancel mass from both sides<br /> Since mass $m$ appears on both sides, it cancels out: **$gh = \frac{1}{2}v^2$**.<br /><br />3. Solve for height $h$<br /> Rearrange to find $h$: **$h = \frac{v^2}{2g}$**.<br /><br />4. Substitute known values<br /> Substitute $v = 18.8 \, \text{m/s}$ and $g = 9.81 \, \text{m/s}^2$: <br /> $h = \frac{(18.8)^2}{2 \times 9.81}$.<br /><br />5. Calculate the height<br /> Compute the value: $h = \frac{353.44}{19.62} \approx 18.01 \, \text{m}$.
Click to rate:

Similar Questions