QuestionApril 18, 2026

9. A fire extinguisher contains 125 moles of compressed carbon dioxide. What is the volume of the gas at a temperature of 27^circ C and a pressure of 1 atm? 30.8 L 277L 2800 L 3080 L

9. A fire extinguisher contains 125 moles of compressed carbon dioxide. What is the volume of the gas at a temperature of 27^circ C and a pressure of 1 atm? 30.8 L 277L 2800 L 3080 L
9. A fire extinguisher contains 125 moles of compressed carbon dioxide. What is the volume of the gas at a temperature of 27^circ C and a pressure of 1 atm? 30.8 L 277L 2800 L 3080 L

Solution
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Answer

3080 L Explanation 1. Identify applicable gas law Use **Ideal Gas Law**: PV = nRT. 2. Convert temperature to Kelvin T = 27 + 273 = 300\ \text{K}. 3. Apply formula V = \frac{nRT}{P} with n = 125 mol, R = 0.0821\ \text{L·atm/(mol·K)}, P = 1 atm: V = \frac{125 \times 0.0821 \times 300}{1}. 4. Calculate V = 125 \times 24.63 = 3078.75 \ \text{L} \approx 3080 \ \text{L}.

Explanation

1. Identify applicable gas law <br /> Use **Ideal Gas Law**: $PV = nRT$. <br /><br />2. Convert temperature to Kelvin <br /> $T = 27 + 273 = 300\ \text{K}$. <br /><br />3. Apply formula <br /> $V = \frac{nRT}{P}$ with $n = 125$ mol, $R = 0.0821\ \text{L·atm/(mol·K)}$, $P = 1$ atm: <br /> $V = \frac{125 \times 0.0821 \times 300}{1}$. <br /><br />4. Calculate <br /> $V = 125 \times 24.63 = 3078.75 \ \text{L} \approx 3080 \ \text{L}$.
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