QuestionApril 19, 2026

Calculate the molar masses of the following chemical compounds. 1) NaBr 2) AgF 3) (NH_(4))_(2)S 4) PbSO_(4) 5) C_(6)H_(12)O_(6) 6) Ca(OH)_(2) 7) KOH 8) Mg(OH)_(2)

Calculate the molar masses of the following chemical compounds. 1) NaBr 2) AgF 3) (NH_(4))_(2)S 4) PbSO_(4) 5) C_(6)H_(12)O_(6) 6) Ca(OH)_(2) 7) KOH 8) Mg(OH)_(2)
Calculate the molar masses of the following chemical compounds. 1) NaBr 2) AgF 3) (NH_(4))_(2)S 4) PbSO_(4) 5) C_(6)H_(12)O_(6) 6) Ca(OH)_(2) 7) KOH 8) Mg(OH)_(2)

Solution
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Answer

1) 102.89 g/mol ### 2) 126.87 g/mol ### 3) 68.14 g/mol ### 4) 303.26 g/mol ### 5) 180.16 g/mol ### 6) 74.10 g/mol ### 7) 56.11 g/mol ### 8) 58.33 g/mol Explanation 1. Recall molar mass formula Molar mass = sum of (atomic mass × number of atoms) for each element in the compound. 2. Use standard atomic masses Na: 22.99, Br: 79.90, Ag: 107.87, F: 18.998, N: 14.01, H: 1.008, S: 32.06, Pb: 207.2, O: 16.00, C: 12.01, Ca: 40.08, K: 39.10, Mg: 24.31. 3. Calculate for each compound 1) **NaBr**: 22.99 + 79.90 = 102.89\ \text{g/mol} 2) **AgF**: 107.87 + 18.998 = 126.868\ \text{g/mol} 3) **(NH_{4})_{2}S**: N: 14.01 \times 2 = 28.02 H: 1.008 \times 8 = 8.064 S: 32.06 Total = 28.02 + 8.064 + 32.06 = 68.144\ \text{g/mol} 4) **PbSO_{4}**: Pb: 207.2 S: 32.06 O: 16.00 \times 4 = 64.00 Total = 207.2 + 32.06 + 64.00 = 303.26\ \text{g/mol} 5) **C_{6}H_{12}O_{6}**: C: 12.01 \times 6 = 72.06 H: 1.008 \times 12 = 12.096 O: 16.00 \times 6 = 96.00 Total = 72.06 + 12.096 + 96.00 = 180.156\ \text{g/mol} 6) **Ca(OH)_{2}**: Ca: 40.08 O: 16.00 \times 2 = 32.00 H: 1.008 \times 2 = 2.016 Total = 40.08 + 32.00 + 2.016 = 74.096\ \text{g/mol} 7) **KOH**: K: 39.10 O: 16.00 H: 1.008 Total = 39.10 + 16.00 + 1.008 = 56.108\ \text{g/mol} 8) **Mg(OH)_{2}**: Mg: 24.31 O: 16.00 \times 2 = 32.00 H: 1.008 \times 2 = 2.016 Total = 24.31 + 32.00 + 2.016 = 58.326\ \text{g/mol}

Explanation

1. Recall molar mass formula<br /> Molar mass = sum of (atomic mass × number of atoms) for each element in the compound.<br />2. Use standard atomic masses<br /> Na: 22.99, Br: 79.90, Ag: 107.87, F: 18.998, N: 14.01, H: 1.008, S: 32.06, Pb: 207.2, O: 16.00, C: 12.01, Ca: 40.08, K: 39.10, Mg: 24.31.<br /><br />3. Calculate for each compound<br /><br />1) **NaBr**: <br />$22.99 + 79.90 = 102.89\ \text{g/mol}$<br /><br />2) **AgF**: <br />$107.87 + 18.998 = 126.868\ \text{g/mol}$<br /><br />3) **$(NH_{4})_{2}S$**: <br />N: $14.01 \times 2 = 28.02$ <br />H: $1.008 \times 8 = 8.064$ <br />S: $32.06$ <br />Total = $28.02 + 8.064 + 32.06 = 68.144\ \text{g/mol}$<br /><br />4) **$PbSO_{4}$**: <br />Pb: $207.2$ <br />S: $32.06$ <br />O: $16.00 \times 4 = 64.00$ <br />Total = $207.2 + 32.06 + 64.00 = 303.26\ \text{g/mol}$<br /><br />5) **$C_{6}H_{12}O_{6}$**: <br />C: $12.01 \times 6 = 72.06$ <br />H: $1.008 \times 12 = 12.096$ <br />O: $16.00 \times 6 = 96.00$ <br />Total = $72.06 + 12.096 + 96.00 = 180.156\ \text{g/mol}$<br /><br />6) **$Ca(OH)_{2}$**: <br />Ca: $40.08$ <br />O: $16.00 \times 2 = 32.00$ <br />H: $1.008 \times 2 = 2.016$ <br />Total = $40.08 + 32.00 + 2.016 = 74.096\ \text{g/mol}$<br /><br />7) **KOH**: <br />K: $39.10$ <br />O: $16.00$ <br />H: $1.008$ <br />Total = $39.10 + 16.00 + 1.008 = 56.108\ \text{g/mol}$<br /><br />8) **$Mg(OH)_{2}$**: <br />Mg: $24.31$ <br />O: $16.00 \times 2 = 32.00$ <br />H: $1.008 \times 2 = 2.016$ <br />Total = $24.31 + 32.00 + 2.016 = 58.326\ \text{g/mol}$
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