QuestionMay 19, 2026

You have a balloon containing 1 L of air at STP in a vacuum chamber. What will the volume of the balloon be when you reduce the pressure by half and increase the temperature to 373 K? Use the combined gas law PV/T=korP_(1)V_(1)/T_(1)=P_(2)V_(2)/T_(2) 0.68 L 1.46 L 2.00 L 2.73 L

You have a balloon containing 1 L of air at STP in a vacuum chamber. What will the volume of the balloon be when you reduce the pressure by half and increase the temperature to 373 K? Use the combined gas law PV/T=korP_(1)V_(1)/T_(1)=P_(2)V_(2)/T_(2) 0.68 L 1.46 L 2.00 L 2.73 L
You have a balloon containing 1 L of air at STP in a vacuum chamber. What will the volume of the balloon be when you reduce the pressure by half and increase the temperature to 373 K? Use the combined gas law PV/T=korP_(1)V_(1)/T_(1)=P_(2)V_(2)/T_(2) 0.68 L 1.46 L 2.00 L 2.73 L

Solution
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Answer

2.73 L Explanation 1. Identify known values P_1 = 1 \ \text{atm}, V_1 = 1.00 \ \text{L}, T_1 = 273 \ \text{K}, P_2 = 0.5 \ \text{atm}, T_2 = 373 \ \text{K}. 2. Apply combined gas law ** \frac{P_1 V_1}{T_1} = \frac{P_2 V_2}{T_2} ** 3. Solve for V_2 V_2 = \frac{P_1 V_1 T_2}{P_2 T_1} = \frac{1.00 \times 1.00 \times 373}{0.5 \times 273} V_2 = \frac{373}{136.5} \approx 2.73 \ \text{L}

Explanation

1. Identify known values <br /> $P_1 = 1 \ \text{atm}$, $V_1 = 1.00 \ \text{L}$, $T_1 = 273 \ \text{K}$, $P_2 = 0.5 \ \text{atm}$, $T_2 = 373 \ \text{K}$. <br />2. Apply combined gas law <br /> **$ \frac{P_1 V_1}{T_1} = \frac{P_2 V_2}{T_2} $** <br />3. Solve for $V_2$ <br /> $V_2 = \frac{P_1 V_1 T_2}{P_2 T_1} = \frac{1.00 \times 1.00 \times 373}{0.5 \times 273}$ <br /> $V_2 = \frac{373}{136.5} \approx 2.73 \ \text{L}$
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