QuestionJuly 24, 2025

If r(x)=3x-1 and s(x)=2x+1 (3(6)-1)/(2(6)+1) ((6))/(2(6)+1) (36-1)/(26+1) ((6)-1)/((6)+1)

If r(x)=3x-1 and s(x)=2x+1 (3(6)-1)/(2(6)+1) ((6))/(2(6)+1) (36-1)/(26+1) ((6)-1)/((6)+1)
If r(x)=3x-1 and s(x)=2x+1
(3(6)-1)/(2(6)+1)
((6))/(2(6)+1)
(36-1)/(26+1)
((6)-1)/((6)+1)

Solution
4.3(225 votes)

Answer

\frac{17}{13} Explanation 1. Evaluate r(x) at x=6 Substitute x=6 into r(x)=3x-1: r(6) = 3(6) - 1 = 18 - 1 = 17. 2. Evaluate s(x) at x=6 Substitute x=6 into s(x)=2x+1: s(6) = 2(6) + 1 = 12 + 1 = 13. 3. Calculate the fraction Use the evaluated values: \frac{r(6)}{s(6)} = \frac{17}{13}.

Explanation

1. Evaluate $r(x)$ at $x=6$<br /> Substitute $x=6$ into $r(x)=3x-1$: $r(6) = 3(6) - 1 = 18 - 1 = 17$.<br />2. Evaluate $s(x)$ at $x=6$<br /> Substitute $x=6$ into $s(x)=2x+1$: $s(6) = 2(6) + 1 = 12 + 1 = 13$.<br />3. Calculate the fraction<br /> Use the evaluated values: $\frac{r(6)}{s(6)} = \frac{17}{13}$.
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