QuestionJuly 24, 2025

Order the expressions by choosing langle ,rangle ,or equiv 7^-2square 7^-1 ((1)/(7))^-1square 7^-2 ((1)/(7))^-2square ((1)/(7))^-1

Order the expressions by choosing langle ,rangle ,or equiv 7^-2square 7^-1 ((1)/(7))^-1square 7^-2 ((1)/(7))^-2square ((1)/(7))^-1
Order the expressions by choosing langle ,rangle  ,or equiv 
7^-2square 7^-1
((1)/(7))^-1square 7^-2
((1)/(7))^-2square ((1)/(7))^-1

Solution
4.3(270 votes)

Answer

7^{-2} \langle 7^{-1}, (\frac{1}{7})^{-1} \rangle 7^{-2}, (\frac{1}{7})^{-2} \rangle (\frac{1}{7})^{-1} Explanation 1. Simplify 7^{-2} and 7^{-1} 7^{-2} = \frac{1}{49} and 7^{-1} = \frac{1}{7}. Thus, 7^{-2} \frac{1}{49}, (\frac{1}{7})^{-1} > 7^{-2}. 3. Simplify (\frac{1}{7})^{-2} and (\frac{1}{7})^{-1} (\frac{1}{7})^{-2} = 7^2 = 49 and (\frac{1}{7})^{-1} = 7. Thus, (\frac{1}{7})^{-2} > (\frac{1}{7})^{-1}.

Explanation

1. Simplify $7^{-2}$ and $7^{-1}$<br /> $7^{-2} = \frac{1}{49}$ and $7^{-1} = \frac{1}{7}$. Thus, $7^{-2} < 7^{-1}$.<br />2. Simplify $(\frac{1}{7})^{-1}$ and compare with $7^{-2}$<br /> $(\frac{1}{7})^{-1} = 7^1 = 7$. Since $7 > \frac{1}{49}$, $(\frac{1}{7})^{-1} > 7^{-2}$.<br />3. Simplify $(\frac{1}{7})^{-2}$ and $(\frac{1}{7})^{-1}$<br /> $(\frac{1}{7})^{-2} = 7^2 = 49$ and $(\frac{1}{7})^{-1} = 7$. Thus, $(\frac{1}{7})^{-2} > (\frac{1}{7})^{-1}$.
Click to rate:

Similar Questions