QuestionMay 20, 2025

An electromagnetic wave traveling through outer space has a frequency of 429 MHz (4.29times 10^8Hz) What is the approximate wavelength of the electromagnetic wave? 0.70 meters B. 1.29 meters C. 1.43 meters 2.28 meters

An electromagnetic wave traveling through outer space has a frequency of 429 MHz (4.29times 10^8Hz) What is the approximate wavelength of the electromagnetic wave? 0.70 meters B. 1.29 meters C. 1.43 meters 2.28 meters
An electromagnetic wave traveling through outer space has a frequency of 429 MHz
(4.29times 10^8Hz)
What is the approximate wavelength of the electromagnetic wave?
0.70 meters
B. 1.29 meters
C. 1.43 meters
2.28 meters

Solution
4.3(259 votes)

Answer

0.70 meters Explanation 1. Identify the formula for wavelength Use the formula for the speed of light c = \lambda \cdot f, where \lambda is the wavelength and f is the frequency. 2. Rearrange the formula to solve for wavelength \lambda = \frac{c}{f}, where c = 3 \times 10^8 \text{ m/s} (speed of light). 3. Calculate the wavelength Substitute f = 4.29 \times 10^8 \text{ Hz} into the formula: \lambda = \frac{3 \times 10^8}{4.29 \times 10^8} \approx 0.699 \text{ meters}.

Explanation

1. Identify the formula for wavelength<br /> Use the formula for the speed of light $c = \lambda \cdot f$, where $\lambda$ is the wavelength and $f$ is the frequency.<br /><br />2. Rearrange the formula to solve for wavelength<br /> $\lambda = \frac{c}{f}$, where $c = 3 \times 10^8 \text{ m/s}$ (speed of light).<br /><br />3. Calculate the wavelength<br /> Substitute $f = 4.29 \times 10^8 \text{ Hz}$ into the formula: $\lambda = \frac{3 \times 10^8}{4.29 \times 10^8} \approx 0.699 \text{ meters}$.
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