QuestionJuly 25, 2025

4. Using your data what is the approximate hydronium ion concentration and hydroxide ion concentration in a cup of tea? Which is higher? (Refer back to the chart of pH if you need to.) (4 points)

4. Using your data what is the approximate hydronium ion concentration and hydroxide ion concentration in a cup of tea? Which is higher? (Refer back to the chart of pH if you need to.) (4 points)
4. Using your data what is the approximate hydronium ion concentration and hydroxide ion concentration in a
cup of tea? Which is higher? (Refer back to the chart of pH if you need to.) (4 points)

Solution
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Answer

Hydronium ion concentration: 1 \times 10^{-5} M; Hydroxide ion concentration: 1 \times 10^{-9} M; Hydronium ion concentration is higher. Explanation 1. Determine pH of Tea Tea typically has a pH around 5. 2. Calculate Hydronium Ion Concentration Use the formula **[H_3O^+] = 10^{-pH}**. For pH = 5, [H_3O^+] = 10^{-5} = 1 \times 10^{-5} M. 3. Calculate Hydroxide Ion Concentration Use the relation **[OH^-] = \frac{10^{-14}} H_3O^+ **. So, [OH^-] = \frac{10^{-14}}{1 \times 10^{-5}} = 1 \times 10^{-9} M. 4. Compare Concentrations Compare [H_3O^+] = 1 \times 10^{-5} M and [OH^-] = 1 \times 10^{-9} M. Hydronium ion concentration is higher.

Explanation

1. Determine pH of Tea<br /> Tea typically has a pH around 5.<br /><br />2. Calculate Hydronium Ion Concentration<br /> Use the formula **$[H_3O^+] = 10^{-pH}$**. For pH = 5, $[H_3O^+] = 10^{-5} = 1 \times 10^{-5}$ M.<br /><br />3. Calculate Hydroxide Ion Concentration<br /> Use the relation **$[OH^-] = \frac{10^{-14}}{[H_3O^+]}$**. So, $[OH^-] = \frac{10^{-14}}{1 \times 10^{-5}} = 1 \times 10^{-9}$ M.<br /><br />4. Compare Concentrations<br /> Compare $[H_3O^+] = 1 \times 10^{-5}$ M and $[OH^-] = 1 \times 10^{-9}$ M. Hydronium ion concentration is higher.
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