QuestionApril 26, 2025

Acar initially moving at a speed of 5.0m/s accelerates at a rate of 3.0m/s for 8.0 seconds. What final speed does the car reach? 35.0m/s 29.0m/s 25.0m/s 31.0m/s Clear my selection

Acar initially moving at a speed of 5.0m/s accelerates at a rate of 3.0m/s for 8.0 seconds. What final speed does the car reach? 35.0m/s 29.0m/s 25.0m/s 31.0m/s Clear my selection
Acar initially moving at a speed of 5.0m/s accelerates at a rate of 3.0m/s for 8.0 seconds. What final speed does the car reach?
35.0m/s
29.0m/s
25.0m/s
31.0m/s
Clear my selection

Solution
4.1(129 votes)

Answer

29.0 \, \text{m/s} Explanation 1. Identify the known values Initial speed u = 5.0 \, \text{m/s}, acceleration a = 3.0 \, \text{m/s}^2, time t = 8.0 \, \text{s}. 2. Use the formula for final velocity Apply **v = u + at** to find the final speed. 3. Calculate the final speed v = 5.0 \, \text{m/s} + (3.0 \, \text{m/s}^2 \times 8.0 \, \text{s}) = 5.0 \, \text{m/s} + 24.0 \, \text{m/s} = 29.0 \, \text{m/s}.

Explanation

1. Identify the known values<br /> Initial speed $u = 5.0 \, \text{m/s}$, acceleration $a = 3.0 \, \text{m/s}^2$, time $t = 8.0 \, \text{s}$.<br /><br />2. Use the formula for final velocity<br /> Apply **$v = u + at$** to find the final speed.<br /><br />3. Calculate the final speed<br /> $v = 5.0 \, \text{m/s} + (3.0 \, \text{m/s}^2 \times 8.0 \, \text{s}) = 5.0 \, \text{m/s} + 24.0 \, \text{m/s} = 29.0 \, \text{m/s}$.
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