QuestionAugust 25, 2025

6) -(2x^3y^2)/(y^2)cdot (2x^(3)^4)

6) -(2x^3y^2)/(y^2)cdot (2x^(3)^4)
6) -(2x^3y^2)/(y^2)cdot (2x^(3)^4)

Solution
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Answer

-\frac{1}{8x^9} Explanation 1. Simplify the expression Cancel y^2 from numerator and denominator. 2. Expand (2x^3)^4 Calculate (2x^3)^4 = 16x^{12}. 3. Simplify further Divide -2x^3 by 16x^{12} to get -\frac{1}{8x^9}.

Explanation

1. Simplify the expression<br /> Cancel $y^2$ from numerator and denominator.<br /><br />2. Expand $(2x^3)^4$<br /> Calculate $(2x^3)^4 = 16x^{12}$.<br /><br />3. Simplify further<br /> Divide $-2x^3$ by $16x^{12}$ to get $-\frac{1}{8x^9}$.
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