QuestionJuly 15, 2025

c. A2kg object moving East at a velocity of 21 meters per second strikes a 20 kilogram object that was at rest. After the collision the 2 kg object moves east with a velocity 1m/s and the 20 kg object moves east with a velocity of 2m/s What is the total momentum of the system before collision.^2 What is the total momentum of the system after the collision.

c. A2kg object moving East at a velocity of 21 meters per second strikes a 20 kilogram object that was at rest. After the collision the 2 kg object moves east with a velocity 1m/s and the 20 kg object moves east with a velocity of 2m/s What is the total momentum of the system before collision.^2 What is the total momentum of the system after the collision.
c. A2kg object moving East at a velocity of 21 meters per second strikes a 20 kilogram object that was at rest. After the collision the 2 kg object moves east with a velocity 1m/s and the 20 kg object moves east with a velocity of 2m/s What is the total momentum of the system before collision.^2 What is the total momentum of the system after the collision.

Solution
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Answer

Total momentum before collision: 42 \, \text{kg m/s} ### Total momentum after collision: 42 \, \text{kg m/s} Explanation 1. Calculate Initial Momentum Use **p = mv** for each object. For the 2 kg object: p_1 = 2 \, \text{kg} \times 21 \, \text{m/s} = 42 \, \text{kg m/s}. For the 20 kg object at rest: p_2 = 20 \, \text{kg} \times 0 \, \text{m/s} = 0 \, \text{kg m/s}. 2. Sum Initial Momentum Total initial momentum is p_{\text{initial}} = p_1 + p_2 = 42 \, \text{kg m/s} + 0 \, \text{kg m/s} = 42 \, \text{kg m/s}. 3. Calculate Final Momentum For the 2 kg object after collision: p_1' = 2 \, \text{kg} \times 1 \, \text{m/s} = 2 \, \text{kg m/s}. For the 20 kg object: p_2' = 20 \, \text{kg} \times 2 \, \text{m/s} = 40 \, \text{kg m/s}. 4. Sum Final Momentum Total final momentum is p_{\text{final}} = p_1' + p_2' = 2 \, \text{kg m/s} + 40 \, \text{kg m/s} = 42 \, \text{kg m/s}.

Explanation

1. Calculate Initial Momentum<br /> Use **$p = mv$** for each object. For the 2 kg object: $p_1 = 2 \, \text{kg} \times 21 \, \text{m/s} = 42 \, \text{kg m/s}$. For the 20 kg object at rest: $p_2 = 20 \, \text{kg} \times 0 \, \text{m/s} = 0 \, \text{kg m/s}$.<br /><br />2. Sum Initial Momentum<br /> Total initial momentum is $p_{\text{initial}} = p_1 + p_2 = 42 \, \text{kg m/s} + 0 \, \text{kg m/s} = 42 \, \text{kg m/s}$.<br /><br />3. Calculate Final Momentum<br /> For the 2 kg object after collision: $p_1' = 2 \, \text{kg} \times 1 \, \text{m/s} = 2 \, \text{kg m/s}$. For the 20 kg object: $p_2' = 20 \, \text{kg} \times 2 \, \text{m/s} = 40 \, \text{kg m/s}$.<br /><br />4. Sum Final Momentum<br /> Total final momentum is $p_{\text{final}} = p_1' + p_2' = 2 \, \text{kg m/s} + 40 \, \text{kg m/s} = 42 \, \text{kg m/s}$.
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