QuestionJuly 8, 2025

For the chemical reaction: UF_(6)+2H_(2)Oarrow UO_(2)F_(2)+4HF write the conversion factor that would be needed led to do each of the following one-step conversions. (a) Moles of UF_(6) to moles of HF square (b) Moles of UO_(2)F_(2) to moles of H_(2)O square (c) Moles of HF to moles of UO_(2)F_(2) square (d) Moles of H_(2)O to moles of UF_(6) square

For the chemical reaction: UF_(6)+2H_(2)Oarrow UO_(2)F_(2)+4HF write the conversion factor that would be needed led to do each of the following one-step conversions. (a) Moles of UF_(6) to moles of HF square (b) Moles of UO_(2)F_(2) to moles of H_(2)O square (c) Moles of HF to moles of UO_(2)F_(2) square (d) Moles of H_(2)O to moles of UF_(6) square
For the chemical reaction: UF_(6)+2H_(2)Oarrow UO_(2)F_(2)+4HF write the conversion factor that would be needed led to do each of the following one-step conversions. (a) Moles of UF_(6) to moles of HF square (b) Moles of UO_(2)F_(2) to moles of H_(2)O square (c) Moles of HF to moles of UO_(2)F_(2) square (d) Moles of H_(2)O to moles of UF_(6) square

Solution
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Answer

(a) \frac{4 \text{ moles HF}}{1 \text{ mole } UF_{6}} ### (b) \frac{2 \text{ moles } H_{2}O}{1 \text{ mole } UO_{2}F_{2}} ### (c) \frac{1 \text{ mole } UO_{2}F_{2}}{4 \text{ moles HF}} ### (d) \frac{1 \text{ mole } UF_{6}}{2 \text{ moles } H_{2}O} Explanation 1. Identify the stoichiometric coefficients From the balanced equation UF_{6} + 2H_{2}O \rightarrow UO_{2}F_{2} + 4HF, identify the coefficients for each substance. 2. Determine conversion factors Use the coefficients to establish conversion factors between substances. (a) **Moles of UF_{6} to moles of HF**: The conversion factor is \frac{4 \text{ moles HF}}{1 \text{ mole } UF_{6}}. (b) **Moles of UO_{2}F_{2} to moles of H_{2}O**: The conversion factor is \frac{2 \text{ moles } H_{2}O}{1 \text{ mole } UO_{2}F_{2}}. (c) **Moles of HF to moles of UO_{2}F_{2}**: The conversion factor is \frac{1 \text{ mole } UO_{2}F_{2}}{4 \text{ moles HF}}. (d) **Moles of H_{2}O to moles of UF_{6}**: The conversion factor is \frac{1 \text{ mole } UF_{6}}{2 \text{ moles } H_{2}O}.

Explanation

1. Identify the stoichiometric coefficients<br /> From the balanced equation $UF_{6} + 2H_{2}O \rightarrow UO_{2}F_{2} + 4HF$, identify the coefficients for each substance.<br /><br />2. Determine conversion factors<br /> Use the coefficients to establish conversion factors between substances.<br /><br />(a) **Moles of $UF_{6}$ to moles of HF**: The conversion factor is $\frac{4 \text{ moles HF}}{1 \text{ mole } UF_{6}}$.<br /><br />(b) **Moles of $UO_{2}F_{2}$ to moles of $H_{2}O$**: The conversion factor is $\frac{2 \text{ moles } H_{2}O}{1 \text{ mole } UO_{2}F_{2}}$.<br /><br />(c) **Moles of HF to moles of $UO_{2}F_{2}$**: The conversion factor is $\frac{1 \text{ mole } UO_{2}F_{2}}{4 \text{ moles HF}}$.<br /><br />(d) **Moles of $H_{2}O$ to moles of $UF_{6}$**: The conversion factor is $\frac{1 \text{ mole } UF_{6}}{2 \text{ moles } H_{2}O}$.
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