QuestionJuly 14, 2025

E and F are sets of real numbers defined as follows. E= zvert zgt 2 F= zvert zleqslant 9 Write Ecap F and Ecup F using interval notation. If the set is empty, write varnothing Ecap F=square Ecup F=square

E and F are sets of real numbers defined as follows. E= zvert zgt 2 F= zvert zleqslant 9 Write Ecap F and Ecup F using interval notation. If the set is empty, write varnothing Ecap F=square Ecup F=square
E and F are sets of real numbers defined as follows.
E= zvert zgt 2 
F= zvert zleqslant 9 
Write Ecap F and Ecup F using interval notation.
If the set is empty, write varnothing 
Ecap F=square 
Ecup F=square

Solution
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Answer

E\cap F=(2, 9] ### E\cup F=(2, 9] Explanation 1. Determine E \cap F The intersection E \cap F includes elements common to both sets. For E = \{ z \mid z > 2 \} and F = \{ z \mid z \leq 9 \}, the overlap is 2 2 \} and F = \{ z \mid z \leq 9 \}, the union covers all real numbers greater than 2 or less than or equal to 9. Thus, E \cup F = (2, 9].

Explanation

1. Determine $E \cap F$<br /> The intersection $E \cap F$ includes elements common to both sets. For $E = \{ z \mid z > 2 \}$ and $F = \{ z \mid z \leq 9 \}$, the overlap is $2 < z \leq 9$. Thus, $E \cap F = (2, 9]$.<br /><br />2. Determine $E \cup F$<br /> The union $E \cup F$ includes all elements from both sets. Since $E = \{ z \mid z > 2 \}$ and $F = \{ z \mid z \leq 9 \}$, the union covers all real numbers greater than 2 or less than or equal to 9. Thus, $E \cup F = (2, 9]$.
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