QuestionJuly 26, 2025

The difference between Q and K_(sp) is no differencé. K_(sp) is the value of the product at equilibrium and Q is the value of the product under any condition. Q is the value of the product at equilibrium and K_(sp) is the value of the product under any condition. Q is greater than K_(sp) K_(sp) is greater than Q.

The difference between Q and K_(sp) is no differencé. K_(sp) is the value of the product at equilibrium and Q is the value of the product under any condition. Q is the value of the product at equilibrium and K_(sp) is the value of the product under any condition. Q is greater than K_(sp) K_(sp) is greater than Q.
The difference between Q and K_(sp) is
no differencé.
K_(sp) is the value of the product at equilibrium and Q is the value of the product under any condition.
Q is the value of the product at equilibrium and K_(sp) is the value of the product under any condition.
Q is greater than K_(sp)
K_(sp) is greater than Q.

Solution
4.7(354 votes)

Answer

K_{sp} is greater than Q. Explanation 1. Define Q and K_{sp} Q is the reaction quotient, representing the product of ion concentrations at any given moment. K_{sp} is the solubility product constant, representing the product of ion concentrations at equilibrium. 2. Compare Q and K_{sp} If Q > K_{sp}, the solution is supersaturated, and precipitation occurs. If Q < K_{sp}, the solution is unsaturated, and more solute can dissolve. If Q = K_{sp}, the solution is at equilibrium.

Explanation

1. Define $Q$ and $K_{sp}$<br /> $Q$ is the reaction quotient, representing the product of ion concentrations at any given moment. $K_{sp}$ is the solubility product constant, representing the product of ion concentrations at equilibrium.<br /><br />2. Compare $Q$ and $K_{sp}$<br /> If $Q > K_{sp}$, the solution is supersaturated, and precipitation occurs. If $Q < K_{sp}$, the solution is unsaturated, and more solute can dissolve. If $Q = K_{sp}$, the solution is at equilibrium.
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