QuestionJuly 15, 2025

Solve the system and find the value of y. 6x+3y=12 5x+3y=0 y= square

Solve the system and find the value of y. 6x+3y=12 5x+3y=0 y= square
Solve the system and find the value of y.
6x+3y=12
5x+3y=0
y=
square

Solution
4.2(210 votes)

Answer

y = -20 Explanation 1. Eliminate y by Subtraction Subtract the second equation from the first: (6x + 3y) - (5x + 3y) = 12 - 0. 2. Simplify the Resulting Equation Simplify to get x: x = 12. 3. Substitute x into One of the Original Equations Use 5x + 3y = 0: 5(12) + 3y = 0. 4. Solve for y Simplify and solve: 60 + 3y = 0 \Rightarrow 3y = -60 \Rightarrow y = -20.

Explanation

1. Eliminate $y$ by Subtraction<br /> Subtract the second equation from the first: $(6x + 3y) - (5x + 3y) = 12 - 0$.<br /><br />2. Simplify the Resulting Equation<br /> Simplify to get $x$: $x = 12$.<br /><br />3. Substitute $x$ into One of the Original Equations<br /> Use $5x + 3y = 0$: $5(12) + 3y = 0$.<br /><br />4. Solve for $y$<br /> Simplify and solve: $60 + 3y = 0 \Rightarrow 3y = -60 \Rightarrow y = -20$.
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