QuestionJune 5, 2025

What volume would 3.01cdot 10^23 molecules of oxygen gas occupy at STP? 11.2 mL 22.4 mL 11.2 L 22.4 L

What volume would 3.01cdot 10^23 molecules of oxygen gas occupy at STP? 11.2 mL 22.4 mL 11.2 L 22.4 L
What volume would 3.01cdot 10^23 molecules of oxygen gas occupy at STP?
11.2 mL
22.4 mL
11.2 L
22.4 L

Solution
4.7(269 votes)

Answer

11.2 L Explanation 1. Determine moles of oxygen Use **Avogadro's number**: \(6.022 \cdot 10^{23}\) molecules/mol. Calculate moles: \(\frac{3.01 \cdot 10^{23}}{6.022 \cdot 10^{23}}\). 2. Calculate volume at STP At STP, 1 mole of gas occupies **22.4 L**. Multiply moles by 22.4 L/mol.

Explanation

1. Determine moles of oxygen<br /> Use **Avogadro's number**: \(6.022 \cdot 10^{23}\) molecules/mol. Calculate moles: \(\frac{3.01 \cdot 10^{23}}{6.022 \cdot 10^{23}}\).<br /><br />2. Calculate volume at STP<br /> At STP, 1 mole of gas occupies **22.4 L**. Multiply moles by 22.4 L/mol.
Click to rate:

Similar Questions