QuestionDecember 16, 2025

d. What volume of 5:00 M Kl stock solution is needed to make 250. mL of a 1.50 M solution? 833 mL 0.030 oml 33.3 mL 75.0 mL

d. What volume of 5:00 M Kl stock solution is needed to make 250. mL of a 1.50 M solution? 833 mL 0.030 oml 33.3 mL 75.0 mL
d. What volume of 5:00 M Kl stock solution is needed to make 250. mL of a 1.50 M
solution?
833 mL
0.030 oml
33.3 mL
75.0 mL

Solution
3.9(245 votes)

Answer

75.0 mL Explanation 1. Use dilution formula Apply M_1V_1 = M_2V_2 where M_1 = 5.00 M, M_2 = 1.50 M, V_2 = 250 mL. 2. Solve for V_1 V_1 = \frac{M_2V_2}{M_1} = \frac{1.50 \times 250}{5.00} = 75.0 mL

Explanation

1. Use dilution formula<br /> Apply $M_1V_1 = M_2V_2$ where $M_1 = 5.00$ M, $M_2 = 1.50$ M, $V_2 = 250$ mL.<br />2. Solve for $V_1$<br /> $V_1 = \frac{M_2V_2}{M_1} = \frac{1.50 \times 250}{5.00} = 75.0$ mL
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