QuestionAugust 26, 2025

Factor the polynomial f(x) Then solve the equation f(x)=0 f(x)=x^3-9x^2+11x+21 The factored form is f(x)=(x+1)(x-3)(x-7) The solution(s) to f(x)=0 is(are) x=-1,3,7 (Use commas to separate answers as needed. If a solution occurs more than once, type the solution only once.)

Factor the polynomial f(x) Then solve the equation f(x)=0 f(x)=x^3-9x^2+11x+21 The factored form is f(x)=(x+1)(x-3)(x-7) The solution(s) to f(x)=0 is(are) x=-1,3,7 (Use commas to separate answers as needed. If a solution occurs more than once, type the solution only once.)
Factor the polynomial f(x) Then solve the equation f(x)=0
f(x)=x^3-9x^2+11x+21
The factored form is f(x)=(x+1)(x-3)(x-7)
The solution(s) to f(x)=0 is(are) x=-1,3,7
(Use commas to separate answers as needed. If a solution occurs more than once, type the solution only once.)

Solution
4.4(318 votes)

Answer

x=-1, 3, 7 Explanation 1. Verify the factored form Multiply (x+1)(x-3)(x-7) to check if it equals x^3 - 9x^2 + 11x + 21. (x+1)(x-3) = x^2 - 3x + x - 3 = x^2 - 2x - 3 (x^2 - 2x - 3)(x-7) = x^3 - 7x^2 - 2x^2 + 14x - 3x + 21 = x^3 - 9x^2 + 11x + 21 The factored form is correct. 2. Solve f(x)=0 Set each factor equal to zero: (x+1)=0, (x-3)=0, (x-7)=0. Solutions are x=-1, x=3, x=7.

Explanation

1. Verify the factored form<br /> Multiply $(x+1)(x-3)(x-7)$ to check if it equals $x^3 - 9x^2 + 11x + 21$.<br /> $(x+1)(x-3) = x^2 - 3x + x - 3 = x^2 - 2x - 3$<br /> $(x^2 - 2x - 3)(x-7) = x^3 - 7x^2 - 2x^2 + 14x - 3x + 21 = x^3 - 9x^2 + 11x + 21$<br /> The factored form is correct.<br /><br />2. Solve $f(x)=0$<br /> Set each factor equal to zero: $(x+1)=0$, $(x-3)=0$, $(x-7)=0$.<br /> Solutions are $x=-1$, $x=3$, $x=7$.
Click to rate: