QuestionAugust 24, 2025

Use the formula S=(n(n+1))/(2) to find the sum of 1+2+3+... +895 1+2+3+... +895=square (Simplify your answer.)

Use the formula S=(n(n+1))/(2) to find the sum of 1+2+3+... +895 1+2+3+... +895=square (Simplify your answer.)
Use the formula S=(n(n+1))/(2) to find the sum of 1+2+3+... +895
1+2+3+... +895=square  (Simplify your answer.)

Solution
4.1(240 votes)

Answer

400960 Explanation 1. Identify the formula Use the formula for the sum of the first n natural numbers: **S=\frac{n(n+1)}{2}**. 2. Substitute the value of n Here, n = 895. Substitute into the formula: S = \frac{895(895+1)}{2}. 3. Simplify the expression Calculate 895 + 1 = 896. Then compute S = \frac{895 \times 896}{2}. 4. Perform the multiplication and division Calculate 895 \times 896 = 801920. Then divide by 2: S = \frac{801920}{2} = 400960.

Explanation

1. Identify the formula<br /> Use the formula for the sum of the first $n$ natural numbers: **$S=\frac{n(n+1)}{2}$**.<br />2. Substitute the value of $n$<br /> Here, $n = 895$. Substitute into the formula: $S = \frac{895(895+1)}{2}$.<br />3. Simplify the expression<br /> Calculate $895 + 1 = 896$. Then compute $S = \frac{895 \times 896}{2}$.<br />4. Perform the multiplication and division<br /> Calculate $895 \times 896 = 801920$. Then divide by 2: $S = \frac{801920}{2} = 400960$.
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