QuestionJune 10, 2025

A graduated cylinder is filled with water to the 25.0 mL mark. After 27.5 g of titanium dioxide (TiO_(2)) is added, the volume is 31.5 mL. Calculate the density of the TiO_(2) to the correct number of significant figures. 0.873g/cm^3 0.87g/cm^3 4.2g/cm^3 4.23g/cm^3 3.1g/cm^3

A graduated cylinder is filled with water to the 25.0 mL mark. After 27.5 g of titanium dioxide (TiO_(2)) is added, the volume is 31.5 mL. Calculate the density of the TiO_(2) to the correct number of significant figures. 0.873g/cm^3 0.87g/cm^3 4.2g/cm^3 4.23g/cm^3 3.1g/cm^3
A graduated cylinder is filled with water to the 25.0 mL mark. After 27.5 g of titanium dioxide (TiO_(2)) is added, the
volume is 31.5 mL. Calculate the density of the TiO_(2) to the correct number of significant figures.
0.873g/cm^3
0.87g/cm^3
4.2g/cm^3
4.23g/cm^3
3.1g/cm^3

Solution
4.7(235 votes)

Answer

4.23 \, \text{g/cm}^3 Explanation 1. Calculate the volume of TiO_{2} Subtract initial water volume from final volume: 31.5 \, \text{mL} - 25.0 \, \text{mL} = 6.5 \, \text{mL}. 2. Convert volume to cm³ Since 1 \, \text{mL} = 1 \, \text{cm}^3, 6.5 \, \text{mL} = 6.5 \, \text{cm}^3. 3. Calculate density of TiO_{2} Use formula: **Density = \frac{\text{mass}}{\text{volume}}**. Density = \frac{27.5 \, \text{g}}{6.5 \, \text{cm}^3}. 4. Perform calculation Density = 4.230769 \, \text{g/cm}^3. Round to correct significant figures: 4.23 \, \text{g/cm}^3.

Explanation

1. Calculate the volume of $TiO_{2}$<br /> Subtract initial water volume from final volume: $31.5 \, \text{mL} - 25.0 \, \text{mL} = 6.5 \, \text{mL}$.<br />2. Convert volume to cm³<br /> Since $1 \, \text{mL} = 1 \, \text{cm}^3$, $6.5 \, \text{mL} = 6.5 \, \text{cm}^3$.<br />3. Calculate density of $TiO_{2}$<br /> Use formula: **Density = $\frac{\text{mass}}{\text{volume}}$**. Density = $\frac{27.5 \, \text{g}}{6.5 \, \text{cm}^3}$.<br />4. Perform calculation<br /> Density = $4.230769 \, \text{g/cm}^3$. Round to correct significant figures: $4.23 \, \text{g/cm}^3$.
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