QuestionJuly 20, 2025

What is the final pressure when the temperature of a cylinder of oxygen at 1800 psig is increased from 50^circ F to 110^circ F

What is the final pressure when the temperature of a cylinder of oxygen at 1800 psig is increased from 50^circ F to 110^circ F
What is the final pressure when the temperature of a cylinder of oxygen at 1800 psig is increased from 50^circ F to 110^circ F

Solution
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Answer

2011.8 psig Explanation 1. Convert Temperatures to Kelvin T_1 = 50^{\circ}F = \frac{5}{9}(50 - 32) + 273.15 = 283.15\,K T_2 = 110^{\circ}F = \frac{5}{9}(110 - 32) + 273.15 = 316.48\,K 2. Apply Gay-Lussac's Law **P_1/T_1 = P_2/T_2**; solve for P_2: P_2 = P_1 \cdot (T_2/T_1) 3. Calculate Final Pressure P_2 = 1800\,psig \cdot (316.48/283.15) = 2011.8\,psig

Explanation

1. Convert Temperatures to Kelvin<br /> $T_1 = 50^{\circ}F = \frac{5}{9}(50 - 32) + 273.15 = 283.15\,K$<br /> $T_2 = 110^{\circ}F = \frac{5}{9}(110 - 32) + 273.15 = 316.48\,K$<br />2. Apply Gay-Lussac's Law<br /> **$P_1/T_1 = P_2/T_2$**; solve for $P_2$: $P_2 = P_1 \cdot (T_2/T_1)$<br />3. Calculate Final Pressure<br /> $P_2 = 1800\,psig \cdot (316.48/283.15) = 2011.8\,psig$
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