QuestionMarch 20, 2026

Use molecular orbital theory to determine the bond order in H_(2) o 2 1 3

Use molecular orbital theory to determine the bond order in H_(2) o 2 1 3
Use molecular orbital theory to determine the bond order in H_(2)
o
2
1
3

Solution
4.7(338 votes)

Answer

1 Explanation 1. Apply molecular orbital theory bond order formula The bond order formula is: **Bond order** = \frac{(\text{Number of bonding electrons} - \text{Number of antibonding electrons})}{2} 2. Determine electron distribution for H_2 Each H atom has 1 electron → total 2 electrons. Both occupy the bonding \sigma_{1s} orbital → bonding electrons = 2, antibonding electrons = 0. 3. Calculate bond order Bond order = \frac{(2 - 0)}{2} = 1

Explanation

1. Apply molecular orbital theory bond order formula <br /> The bond order formula is: <br />**Bond order** $= \frac{(\text{Number of bonding electrons} - \text{Number of antibonding electrons})}{2}$ <br /><br />2. Determine electron distribution for $H_2$ <br /> Each $H$ atom has 1 electron → total 2 electrons. Both occupy the bonding $\sigma_{1s}$ orbital → bonding electrons = 2, antibonding electrons = 0.<br /><br />3. Calculate bond order <br /> Bond order $= \frac{(2 - 0)}{2} = 1$
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