QuestionJuly 20, 2025

question A new system addition to the building is tied into the existing system mains using a rolling offset.The rolling offset consists of two flanged 22(1)/(2)^circ ells and a diagonal pipe assembly. The main pipe size is 6".The new main location is 1' higher and offset 2 horizontally from the existing main. The center-to center measurement of the offset pipe assembly is __ Round decimals to three places.Round all fractions to the nearest (1)/(8)th Refer to the appendix for fitting takeouts and allowances. Select one: a. 5'-10(1)/(8)'' b. 5'-2(5)/(8)'' C. . 6' d. 9'-10(1)/(8)'' e. 8'

question A new system addition to the building is tied into the existing system mains using a rolling offset.The rolling offset consists of two flanged 22(1)/(2)^circ ells and a diagonal pipe assembly. The main pipe size is 6".The new main location is 1' higher and offset 2 horizontally from the existing main. The center-to center measurement of the offset pipe assembly is __ Round decimals to three places.Round all fractions to the nearest (1)/(8)th Refer to the appendix for fitting takeouts and allowances. Select one: a. 5'-10(1)/(8)'' b. 5'-2(5)/(8)'' C. . 6' d. 9'-10(1)/(8)'' e. 8'
question A new system addition to the building is tied into the existing system mains using a rolling offset.The rolling offset consists of two flanged 22(1)/(2)^circ ells and a diagonal pipe assembly. The main pipe size is 6".The new main location is 1' higher and offset 2 horizontally from the existing main. The center-to center measurement of the offset pipe assembly is __ Round decimals to three places.Round all fractions to the nearest (1)/(8)th Refer to the appendix for fitting takeouts and allowances. Select one: a. 5'-10(1)/(8)'' b. 5'-2(5)/(8)'' C. . 6' d. 9'-10(1)/(8)'' e. 8'

Solution
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Answer

b. 5'-2\frac{5}{8}'' Explanation 1. Calculate the Travel Length Use the formula for travel in a rolling offset: **Travel = \frac{\text{Offset}}{\sin(\text{Angle})}**. Here, Offset = \sqrt{(1')^2 + (2')^2} and Angle = 22.5^{\circ}. 2. Compute the Offset Offset = \sqrt{(1')^2 + (2')^2} = \sqrt{1 + 4} = \sqrt{5} feet. 3. Calculate the Travel Travel = \frac{\sqrt{5}}{\sin(22.5^{\circ})}. Using \sin(22.5^{\circ}) \approx 0.3827, Travel = \frac{\sqrt{5}}{0.3827} \approx 5.236 feet. 4. Round to Nearest Fraction Convert 5.236 feet to feet and inches: 5 feet and 0.236 feet. 0.236 feet \times 12 \approx 2.832 inches. Round 2.832 to nearest \frac{1}{8} inch: 2\frac{5}{8} inches.

Explanation

1. Calculate the Travel Length<br /> Use the formula for travel in a rolling offset: **Travel = \frac{\text{Offset}}{\sin(\text{Angle})}**. Here, Offset = $\sqrt{(1')^2 + (2')^2}$ and Angle = $22.5^{\circ}$.<br /><br />2. Compute the Offset<br /> Offset = $\sqrt{(1')^2 + (2')^2} = \sqrt{1 + 4} = \sqrt{5}$ feet.<br /><br />3. Calculate the Travel<br /> Travel = $\frac{\sqrt{5}}{\sin(22.5^{\circ})}$. Using $\sin(22.5^{\circ}) \approx 0.3827$, Travel = $\frac{\sqrt{5}}{0.3827} \approx 5.236$ feet.<br /><br />4. Round to Nearest Fraction<br /> Convert 5.236 feet to feet and inches: 5 feet and 0.236 feet. 0.236 feet $\times 12 \approx 2.832$ inches. Round 2.832 to nearest $\frac{1}{8}$ inch: $2\frac{5}{8}$ inches.
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