QuestionAugust 26, 2025

The coordinates of the endpoints of FG are F(-7,-6) and G(1,2) . Point H is on FG and divides it such that FH:GH is 3:1 . What are the coordinates of H?

The coordinates of the endpoints of FG are F(-7,-6) and G(1,2) . Point H is on FG and divides it such that FH:GH is 3:1 . What are the coordinates of H?
The coordinates of the endpoints of FG are
F(-7,-6) and G(1,2)
. Point H is on FG and
divides it such that FH:GH is 3:1 . What
are the coordinates of H?

Solution
3.9(218 votes)

Answer

(-1, 0) Explanation 1. Use Section Formula The section formula for internal division is **H(x, y) = \left(\frac{mx_2 + nx_1}{m+n}, \frac{my_2 + ny_1}{m+n}\right)** where m:n is the ratio. 2. Substitute Values Here, x_1 = -7, y_1 = -6, x_2 = 1, y_2 = 2, and the ratio m:n = 3:1. Substitute these into the formula: H(x, y) = \left(\frac{3 \times 1 + 1 \times (-7)}{3+1}, \frac{3 \times 2 + 1 \times (-6)}{3+1}\right). 3. Calculate Coordinates Calculate x: \frac{3 \times 1 + 1 \times (-7)}{4} = \frac{3 - 7}{4} = \frac{-4}{4} = -1. Calculate y: \frac{3 \times 2 + 1 \times (-6)}{4} = \frac{6 - 6}{4} = \frac{0}{4} = 0.

Explanation

1. Use Section Formula<br /> The section formula for internal division is **$H(x, y) = \left(\frac{mx_2 + nx_1}{m+n}, \frac{my_2 + ny_1}{m+n}\right)$** where $m:n$ is the ratio.<br />2. Substitute Values<br /> Here, $x_1 = -7$, $y_1 = -6$, $x_2 = 1$, $y_2 = 2$, and the ratio $m:n = 3:1$. Substitute these into the formula:<br /> $H(x, y) = \left(\frac{3 \times 1 + 1 \times (-7)}{3+1}, \frac{3 \times 2 + 1 \times (-6)}{3+1}\right)$.<br />3. Calculate Coordinates<br /> Calculate $x$: $\frac{3 \times 1 + 1 \times (-7)}{4} = \frac{3 - 7}{4} = \frac{-4}{4} = -1$.<br /> Calculate $y$: $\frac{3 \times 2 + 1 \times (-6)}{4} = \frac{6 - 6}{4} = \frac{0}{4} = 0$.
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