QuestionMarch 3, 2026

17k^2m^3 2x+1 126x^4yz 8 21xyz 147xy

17k^2m^3 2x+1 126x^4yz 8 21xyz 147xy
17k^2m^3	2x+1
126x^4yz 8
21xyz
147xy

Solution
4.6(338 votes)

Answer

\frac{17k^{2}m^{3}}{2x+1},\ \frac{63}{4}x^{4}yz,\ \frac{1}{7}z Explanation 1. Interpret given terms The data appears to be a set of monomials split across lines. We'll simplify ratios/fractions where applicable. 2. Simplify first ratio \frac{17k^{2}m^{3}}{2x+1} cannot be reduced without knowing if 2x+1 is a factor, so it stays as is. 3. Simplify second ratio \frac{126x^{4}yz}{8} = \frac{126}{8}x^{4}yz = \frac{63}{4}x^{4}yz. 4. Simplify third ratio \frac{21xyz}{147xy} = \frac{21}{147} \cdot \frac{xyz}{xy} = \frac{1}{7}z.

Explanation

1. Interpret given terms <br /> The data appears to be a set of monomials split across lines. We'll simplify ratios/fractions where applicable. <br /><br />2. Simplify first ratio <br /> $\frac{17k^{2}m^{3}}{2x+1}$ cannot be reduced without knowing if $2x+1$ is a factor, so it stays as is. <br /><br />3. Simplify second ratio <br /> $\frac{126x^{4}yz}{8} = \frac{126}{8}x^{4}yz = \frac{63}{4}x^{4}yz$. <br /><br />4. Simplify third ratio <br /> $\frac{21xyz}{147xy} = \frac{21}{147} \cdot \frac{xyz}{xy} = \frac{1}{7}z$.
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