QuestionMarch 3, 2026

Part 3: Complex Numbers For each problem below simplify and write the result in n a+bi format. a+bi 5. (6-7i)-(12+-4i) 6. (2-5i)(3+8i)

Part 3: Complex Numbers For each problem below simplify and write the result in n a+bi format. a+bi 5. (6-7i)-(12+-4i) 6. (2-5i)(3+8i)
Part 3: Complex Numbers
For each problem below simplify and write the result in n a+bi format. a+bi
5. (6-7i)-(12+-4i)
6. (2-5i)(3+8i)

Solution
4.1(165 votes)

Answer

5. -6 - 3i ### 6. 46 + i Explanation 1. Simplify subtraction (6 - 7i) - (12 + (-4i)) = 6 - 7i - 12 + 4i = (6 - 12) + (-7i + 4i) = -6 - 3i 2. Simplify multiplication Use **(a+bi)(c+di) = ac + adi + bci + bdi^2**, with i^2 = -1: (2 - 5i)(3 + 8i) = 2\cdot 3 + 2\cdot 8i + (-5i)\cdot 3 + (-5i)\cdot 8i = 6 + 16i - 15i - 40i^2 = 6 + (16i - 15i) - 40(-1) = 6 + i + 40 = 46 + i

Explanation

1. Simplify subtraction <br /> $(6 - 7i) - (12 + (-4i)) = 6 - 7i - 12 + 4i = (6 - 12) + (-7i + 4i) = -6 - 3i$ <br /><br />2. Simplify multiplication <br /> Use **$(a+bi)(c+di) = ac + adi + bci + bdi^2$**, with $i^2 = -1$: <br /> $(2 - 5i)(3 + 8i) = 2\cdot 3 + 2\cdot 8i + (-5i)\cdot 3 + (-5i)\cdot 8i$ <br /> $= 6 + 16i - 15i - 40i^2$ <br /> $= 6 + (16i - 15i) - 40(-1)$ <br /> $= 6 + i + 40 = 46 + i$
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