QuestionSeptember 20, 2025

Problem 17 A tiger leaps horizontally from a 7.5-m-high rock with a speed of 3.0m/sec How far from the base of the rock will she land?

Problem 17 A tiger leaps horizontally from a 7.5-m-high rock with a speed of 3.0m/sec How far from the base of the rock will she land?
Problem 17
A tiger leaps horizontally from a 7.5-m-high rock with a speed of 3.0m/sec How far
from the base of the rock will she land?

Solution
4.3(209 votes)

Answer

3.7\,m (rounded to two significant figures) Explanation 1. Calculate time to fall Use h = \frac{1}{2}gt^2; solve for t: t = \sqrt{\frac{2h}{g}} = \sqrt{\frac{2 \times 7.5}{9.8}} \approx 1.24\,s 2. Calculate horizontal distance Use d = vt; d = 3.0 \times 1.24 = 3.72\,m

Explanation

1. Calculate time to fall<br /> Use $h = \frac{1}{2}gt^2$; solve for $t$: $t = \sqrt{\frac{2h}{g}} = \sqrt{\frac{2 \times 7.5}{9.8}} \approx 1.24\,s$<br />2. Calculate horizontal distance<br /> Use $d = vt$; $d = 3.0 \times 1.24 = 3.72\,m$
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