QuestionJuly 14, 2025

7. a) A rectangular jewelry box is designed such that its length is twice its width and its depth is 2 inches less than its width. The volume of the box is 64 cubic inches. What are the dimensions of the box? (7.2)

7. a) A rectangular jewelry box is designed such that its length is twice its width and its depth is 2 inches less than its width. The volume of the box is 64 cubic inches. What are the dimensions of the box? (7.2)
7. a) A rectangular jewelry box is designed such that its length is twice its width and its depth is 2
inches less than its width. The volume of the box is 64 cubic inches. What are the dimensions of the
box? (7.2)

Solution
4.0(125 votes)

Answer

Width = 4 inches, Length = 8 inches, Depth = 2 inches. Explanation 1. Define Variables Let width = w, length = 2w, depth = w - 2. 2. Set Up Volume Equation Volume = length × width × depth. So, 2w \cdot w \cdot (w - 2) = 64. 3. Simplify and Solve the Equation 2w^2(w - 2) = 64. Simplify to 2w^3 - 4w^2 = 64. Divide by 2: w^3 - 2w^2 = 32. 4. Factor and Solve for Width Rearrange: w^3 - 2w^2 - 32 = 0. Test values: w = 4 satisfies the equation. 5. Calculate Other Dimensions Length = 2w = 8, Depth = w - 2 = 2.

Explanation

1. Define Variables<br /> Let width = $w$, length = $2w$, depth = $w - 2$.<br /><br />2. Set Up Volume Equation<br /> Volume = length × width × depth. So, $2w \cdot w \cdot (w - 2) = 64$.<br /><br />3. Simplify and Solve the Equation<br /> $2w^2(w - 2) = 64$. Simplify to $2w^3 - 4w^2 = 64$. Divide by 2: $w^3 - 2w^2 = 32$.<br /><br />4. Factor and Solve for Width<br /> Rearrange: $w^3 - 2w^2 - 32 = 0$. Test values: $w = 4$ satisfies the equation.<br /><br />5. Calculate Other Dimensions<br /> Length = $2w = 8$, Depth = $w - 2 = 2$.
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