QuestionDecember 15, 2025

e. How many molecules are in 48.0 grams of NaOH? f. How many grams are in 4.63times 10^24 moles of CCl_(4)

e. How many molecules are in 48.0 grams of NaOH? f. How many grams are in 4.63times 10^24 moles of CCl_(4)
e. How many molecules are in 48.0 grams of NaOH? f. How many grams are in 4.63times 10^24 moles of CCl_(4)

Solution
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Answer

7.23 \times 10^{23} molecules of NaOH; 7.13 \times 10^{26} grams of CCl_4. Explanation 1. Calculate moles of NaOH Molar mass of NaOH = 23.0 + 16.0 + 1.0 = 40.0 g/mol. Moles = \frac{48.0}{40.0} = 1.20 mol. 2. Calculate molecules using Avogadro’s number Molecules = 1.20 \times 6.022 \times 10^{23} = 7.226 \times 10^{23}. 3. Calculate grams of CCl_4 Molar mass of CCl_4 = 12.0 + (4 \times 35.5) = 154.0 g/mol. Grams = 4.63 \times 10^{24} \text{ mol} \times 154.0 g/mol.

Explanation

1. Calculate moles of NaOH<br /> Molar mass of NaOH = $23.0 + 16.0 + 1.0 = 40.0$ g/mol. Moles = $\frac{48.0}{40.0} = 1.20$ mol.<br />2. Calculate molecules using Avogadro’s number<br /> Molecules = $1.20 \times 6.022 \times 10^{23} = 7.226 \times 10^{23}$.<br /><br />3. Calculate grams of $CCl_4$<br /> Molar mass of $CCl_4 = 12.0 + (4 \times 35.5) = 154.0$ g/mol. Grams = $4.63 \times 10^{24} \text{ mol} \times 154.0$ g/mol.
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